Home
Class 12
CHEMISTRY
In the given reaction N(2)(g)+O(2)(g) hA...

In the given reaction `N_(2)(g)+O_(2)(g) hArr 2NO(g)`, equilibrium means that

A

Concentration of reactants changes whereas concentration of products is constant

B

Concentration of all substances is constant

C

Concentration of reactants is constant where as concentration of products changes

D

Concentration of all substances changes

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the equilibrium of the reaction \( N_2(g) + O_2(g) \rightleftharpoons 2NO(g) \), we need to understand what equilibrium means in the context of chemical reactions. ### Step-by-Step Solution: 1. **Understanding Equilibrium**: - In a chemical reaction, equilibrium is reached when the rate of the forward reaction (reactants forming products) equals the rate of the reverse reaction (products forming reactants). 2. **Concentration of Reactants and Products**: - At equilibrium, the concentrations of the reactants \( N_2 \) and \( O_2 \), and the product \( NO \) do not change over time. This means that although the reactions are still occurring, the overall concentrations remain constant. 3. **Analyzing the Options**: - **Option A**: Concentration of reactant changes whereas concentration of product is constant. (Incorrect) - **Option B**: Concentration of all substances is constant. (Correct) - **Option C**: Concentration of reactant is constant whereas concentration of product changes. (Incorrect) - **Option D**: Concentration of all substances change. (Incorrect) 4. **Conclusion**: - The correct interpretation of equilibrium in this reaction is that the concentration of all substances (both reactants and products) remains constant at equilibrium. Therefore, the correct answer is **Option B**.
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL EQUILIBRIUM

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE - B|10 Videos

  • CHEMICAL EQUILIBRIUM

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE - C|10 Videos

  • CHEMICAL EQUILIBRIUM

    VMC MODULES ENGLISH|Exercise PRACTICE EXERCISE-4|5 Videos

  • CHEMICAL BONDING-I & II

    VMC MODULES ENGLISH|Exercise JEE Advanced (Archive)|98 Videos

  • CHEMICAL KINETICS

    VMC MODULES ENGLISH|Exercise JEE Advanced (Archive)|52 Videos

Similar Questions

Explore conceptually related problems

For the reaction N_(2)(g)+O_(2)(g) hArr 2NO(g) , the equilibrium constant is K_(1) . The equilibrium constant is K_(2) for the reaction 2NO(g)+O_(2) hArr 2NO_(2)(g) What is K for the reaction NO_(2)(g) hArr 1/2 N_(2)(g)+O_(2)(g) ?

A tenfold increase in pressure on the reaction N_(2)(g)+3H_(2)(g) hArr 2NH_(3)(g) at equilibrium result in ……….. in K_(p) .

For the reaction N_2(g) +O_2( g) hArr 2NO(g), the equilibrium constant is K1 and for reaction 2NO(g) +O_2(g) hArr 2NO_2(g) . equilibrium constant is K2 What is K for the reaction NO_2(g) hArr (1)/(2) N_2(g) + O_2(g)

For the reaction, N_2(g) +O_2(g) hArr 2NO(g) Equilibrium constant k_c=2 Degree of association is

For the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) , the equilibrium can be shifted in favour of product by

The equilibrium constant for the given reaction is 100. N_(2)(g)+2O_(2)(g) hArr 2NO_(2)(g) What is the equilibrium constant for the reaction ? NO_(2)(g) hArr 1//2 N_(2)(g) +O_(2)(g)

If the equilibrium constant for N_(2) (g) + O_(2)(g) hArr 2NO(g) is K , the equilibrium " constant for " 1/2 N_(2) (g) +1/2 O_(2) (g) hArr NO (g) will be

For the reaction H_(2)(g)+I_(2)(g)hArr2HI(g) the equilibrium constant K_(p) changes with

For the reaction H_(2)(g)+I_(2)(g)hArr2HI(g) the equilibrium constant K_(p) changes with

In the equilibrium constant for N_(2)(g) + O_(2)(g)hArr2NO(g) is K, the equilibrium constant for (1)/(2) N_(2)(g) + (1)/(2)O_(2)(g)hArrNO(g) will be: