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The equilibrium of the reaction N(2)(g)+...

The equilibrium of the reaction `N_(2)(g)+3H_(2)(g) hArr 2NH_(3)(g)` will be shifted to the right when:

A

`K_(p) lt Q`

B

`Q lt K_(p)`

C

`Q=K_(p)`

D

`Q lt 2K_(p)`

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The correct Answer is:
To determine when the equilibrium of the reaction \( N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g) \) will shift to the right, we need to analyze the factors that influence chemical equilibrium based on Le Chatelier's principle. ### Step-by-Step Solution: 1. **Understand the Reaction**: The given reaction is: \[ N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g) \] This is a synthesis reaction where nitrogen and hydrogen gases combine to form ammonia. 2. **Identify the Reaction Quotient (Q) and Equilibrium Constant (Kp)**: - The reaction quotient \( Q \) is calculated using the concentrations of the reactants and products at any point in time: \[ Q = \frac{[NH_3]^2}{[N_2][H_2]^3} \] - The equilibrium constant \( K_p \) is the value of \( Q \) when the system is at equilibrium. 3. **Determine the Direction of Shift**: - According to Le Chatelier's principle, if a system at equilibrium is disturbed, it will shift in the direction that counteracts the disturbance. - The equilibrium will shift to the right (towards products) if \( Q < K_p \). This means that there are more reactants than what is present at equilibrium, prompting the reaction to produce more products. 4. **Factors that Shift Equilibrium to the Right**: - **Increase in Reactants**: Adding more \( N_2 \) or \( H_2 \) will shift the equilibrium to the right. - **Decrease in Products**: Removing \( NH_3 \) will also shift the equilibrium to the right. - **Increase in Pressure**: Since there are 4 moles of gas on the reactant side (1 mole of \( N_2 \) and 3 moles of \( H_2 \)) and 2 moles on the product side (2 moles of \( NH_3 \)), increasing the pressure will shift the equilibrium to the side with fewer moles of gas, which is the right side in this case. - **Increase in Temperature**: If the reaction is exothermic, increasing the temperature will shift the equilibrium to the left. Conversely, if it is endothermic, it will shift to the right. 5. **Conclusion**: The equilibrium of the reaction will shift to the right when: - The concentration of reactants increases. - The concentration of products decreases. - The pressure is increased. - The temperature is adjusted favorably (depending on the nature of the reaction).
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