Home
Class 12
CHEMISTRY
At a certain temperature, the vapour pre...

At a certain temperature, the vapour pressure of pure ether is `640 mm` and that of pure acetone is `280 mm`. Calculate the mole fraction of each component in the vapour state if the mole fraction of ether in the solution is `0.50.`

Text Solution

Verified by Experts

In the given solution, both ether and acetone are volatile, so from Raoult’s Law, we can have vapour pressure of solution `(P_("Total"))`.
Let A : ether and B : acetone.
`P_("Total") =P_A+P_B =P_A^0chi_A+P_B^0chi_B`
`rArr P_("Total")= 646 xx0.5+283xx0.5 =464.5 mm`
Now mole fraction in vapour state is given as follows
`chi_A("vapour") =(P_A)/(P_("Total")) =(P_A^0chi_A)/(P_(" Total"))=(646xx0.5)/(464.5)=0.695`
`chi_B ("vapour")=(P_B)/(P_"Total")=(P_B^0chi_B)/(P_"Total")=(283xx0.5)/(464.5)=0.305`
Promotional Banner

Topper's Solved these Questions

  • LIQUID SOLUTIONS

    VMC MODULES ENGLISH|Exercise illustrating the concept|5 Videos

  • LIQUID SOLUTIONS

    VMC MODULES ENGLISH|Exercise SOLVED EXAMPLES|20 Videos

  • LIQUID SOLUTION

    VMC MODULES ENGLISH|Exercise IMPECCABLE|100 Videos

  • MOCK TEST 1

    VMC MODULES ENGLISH|Exercise PART II : CHEMISTRY (SECTION-2)|10 Videos

Similar Questions

Explore conceptually related problems

At a particular temperature why is the vapour pressure of acetone less than that of ether?

The vapour pressure of a pure liquid at 25^(@)C is 100 mm Hg. Calculate the relative lowering of vapour pressure if the mole fraction of solvent in solution is 0.8.

At 25^(@)C , the vapour pressure of pure water is 25.0 mm Hg . And that of an aqueous dilute solution of urea is 20 mm Hg . Calculate the molality of the solution.

The vapour pressure of pure benzene at 25^@C is 640 mm Hg and that of the solute A in benzene is 630 mm of Hg. The molality of solution of

Two liquids, A and B form an ideal solution. At the specified temperature, the vapour pressure of pure A is 20 mm Hg while that of pure B is 75 mm Hg . If the vapour over the mixture consists of 50 mol percent A , what is the mole percent A in the liquid?

The vapour pressure of an aqueous solution of glucose is 750 mm of Hg at 373 K . Calculate molality and mole fraction of solute.

The vapour pressure of pure benzene and toluene are 160 and 60 torr respectively. The mole fraction of toluene in vapour phase in contact with equimolar solution of benzene and toluene is:

The vapour pressure of pure liquid solvent A is 0.80 atm . When a non-volatile substance B is added to the solvent, its vapour pressure drops to 0.60 atm , the mole fraction of component B in the solution is

At 35^(@)C the vapour pressure of pure chloroform is 0.359 at atm and that of pure acetone is 0.453 atm. A solution containing 1 mole of chloroform and 4 mole of acetone has a vapour pressure of (in atm)

The vapour pressure of a certain pure liquid A at 298 K is 40 mbar. When a solution of B is prepared in A at the same temperature, the vapour pressure is found to be 32 mbar. The mole fraction of A in the solution is