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The vapour pressure of pure water at 25@...

The vapour pressure of pure water at `25@ C` is `23.00` torr. What is the vapour pressure of `100 g`of water to which `100 g` of `C_(6)H_(12)O_(6)` (glucose) has been added ?

Text Solution

Verified by Experts

Raoult's Law : `P_("solution")=P_A =P_A^0chi_A`
`rArr P_("solution") =P_A^0(n_B)/(n_A+n_B)=P_A^0 ((g_A)/(M_A))/((g_A)/(M_A)+(g_B)/(M_B))`
`rArr P_("solution"= 23.76 xx((100)/(18))/((100)/(18)+(100)/(180))`
`[M_("Glucose")= 180gm//mol:P_A^0(23.76 "torr")]`
`rArr P_("solution")=21.6 `torr
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