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The vapour pressure of a dilute aqueous ...

The vapour pressure of a dilute aqueous solution of glucosse `(C_(6)H_(12)O_(6))` is `750 mm Hg` at `273 K`. Calculate (a) molality and (b) mole fraction of the solute.

Text Solution

Verified by Experts

Given that : Temperature = 273 K and Boiling point of `H_2O = 373K`
` therefore` Vapour pressure of `H_2O= 76 cm`
We have `(p^@-p)/(p^@) =(wxxM)/(mxxW)` therefore Molality `=w/(mxxW) xx1000 = (p^@-p_s)/(p^@)xx1/Mxx1000=(760-750)/(760)xx1/(18)xx1000 =0.730 mol//kg` of solvent
Also we have `(p^@-p_s)/(p^@)=n/(n+N)` therefore Mole fraction = `(p^@-p_s)/(p^@)=(760-750)/(760)=(10)/(760)=0.013`
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