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The molal freezing point constant of wat...

The molal freezing point constant of water is `1.86 K m^(-1)`. If `342 g` of cane sugar `(C_(12)H_(22)O_(11))` is dissolved in `1000 g` of water, the solution will freeze at

A

`-1.86^@C`

B

`1.86^@C`

C

`-3.92.^@C`

D

`2.42^@C`

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaT_f=(1000xxK_fxx w)/(MW) =(1000xx1.86xx34.2)/(100xx342)=186^@`
`therefore T_f =0 -1.86 =-1.86^@C`
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