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The vapour pressure of CS(2) at 50^(@)C ...

The vapour pressure of `CS_(2)` at `50^(@)C` is `854 "torr"` and a solution of `2.0 g` sulphur in `100 g` of `CS_(2)` has vapour pressure `848.9 "torr"`. If the formula of sulphur molecule is `S_(n)`, then calculate the value of `n`. (at mass of `S = 32`).

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AI Generated Solution

To solve the problem, we will use Raoult's law, which relates the vapor pressure of a solution to the vapor pressure of the pure solvent and the concentration of the solute. Here are the steps to find the value of \( n \) in the formula of the sulfur molecule \( S_n \). ### Step 1: Calculate the relative lowering of vapor pressure Using Raoult's law, the relative lowering of vapor pressure can be calculated as follows: \[ \text{Relative lowering} = \frac{P_0 - P}{P_0} \] ...
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