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The freezing point of an aqueous solutio...

The freezing point of an aqueous solution of non-electrolyte having an osmotic pressure of 2.0 atm at 300 K will be, `(K_(f) "for " H_(2)O = 1.86K mol^(-1)g)` and R = 0.0821 litre atm `K^(-1) mol^(-1)` . Assume molarity and molarity to be same :

Text Solution

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`pi=CRT rArr 2=Cxx0.0821 xx300 rArr C=0.08 ~~m`
`rArr DeltaT_f=K_f.m=1.86xx0.08 = 0.15^@C`
Thus ,`T_f=T_f^0-DeltaT_f=0-0.15^@C=-0.15^@C`
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