Reduction of `gtC=O` to `CH_(2)` can be carried out with

Options

A. Catalytic reduction
B. `Na//C_(2) H_(5)OH`
C. Wolff-Kishner reduction
D. `LiAlH_(4)`

Answer

To solve the question regarding the reduction of a carbonyl group (C=O) to a methylene group (CH2), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Functional Group**:
The carbonyl group (C=O) can be part of an aldehyde or a ketone. The goal is to reduce this functional group to a methylene group (CH2).

2. **Choose the Reducing Agent**:
We need to select an appropriate reducing agent that can facilitate the reduction of the carbonyl group to a methylene group. The options provided include:
- Catalytic reduction
- Sodium in ethanol
- Wolf-Krishner reduction
- Lithium aluminum hydride

3. **Evaluate the Options**:
- **Catalytic Reduction**: Typically used for alkenes and not suitable for reducing carbonyls to hydrocarbons.
- **Sodium in Ethanol**: Generally used for elimination reactions and not for reducing carbonyls to hydrocarbons.
- **Wolf-Krishner Reduction**: This method is specifically designed for reducing carbonyl compounds to hydrocarbons. It involves the use of hydrazine (NH2NH2) followed by a strong base (KOH) and ethylene glycol.
- **Lithium Aluminum Hydride (LiAlH4)**: This is a strong reducing agent that can reduce carbonyls to alcohols but not directly to hydrocarbons.

4. **Select the Correct Method**:
The Wolf-Krishner reduction is the correct choice for reducing a carbonyl group to a methylene group. The reaction proceeds as follows:
- The carbonyl compound reacts with hydrazine to form a hydrazone.
- Upon heating with KOH and ethylene glycol, nitrogen gas is eliminated, resulting in the formation of the hydrocarbon (methylene group).

5. **Conclusion**:
Therefore, the reduction of the carbonyl group (C=O) to a methylene group (CH2) can be effectively carried out using the Wolf-Krishner reduction method.

### Final Answer:
The reduction of C=O to CH2 can be carried out with **Wolf-Krishner reduction**.

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