When benzyl alcohol is oxidised with hot acidic `KMnO_(4)` , the product obtained is `:`

Options

A. Benzaldehyde
B. Benzoic acid
C. `CO_(2)` and `H_(2)O`
D. None of these

Answer

To solve the question of what product is obtained when benzyl alcohol is oxidized with hot acidic KMnO4, we can follow these steps:

### Step 1: Understand the Reactants
Benzyl alcohol (C6H5CH2OH) is an alcohol that contains a benzene ring attached to a CH2OH group.

### Step 2: Identify the Oxidizing Agent
KMnO4 (potassium permanganate) is a strong oxidizing agent, especially in acidic conditions. It can oxidize alcohols to their corresponding carbonyl compounds or carboxylic acids.

### Step 3: Predict the Reaction
When benzyl alcohol is oxidized, the hydroxyl group (-OH) will be converted to a carbonyl group (C=O), and since benzyl alcohol is a primary alcohol, it will be oxidized all the way to a carboxylic acid.

### Step 4: Determine the Product
The oxidation of benzyl alcohol will yield benzoic acid (C6H5COOH) as the final product. The reaction can be summarized as:
\[ \text{C6H5CH2OH} \xrightarrow{\text{KMnO4, H+}} \text{C6H5COOH} \]

### Conclusion
Thus, the product obtained when benzyl alcohol is oxidized with hot acidic KMnO4 is **benzoic acid**.

### Final Answer
**Benzoic acid**

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