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A compound (X) having the molecfular for...

A compound (X) having the molecfular formula `C_(3)H_(9)N` reacts with benzenesulphonyl chloride to form a solild insoluble in alkali is . The compound (X) is

A

`CH_(3)CH_(2)CH_(2)NH_(2)`

B

`(CH_(3))_(2)CHNH_(2)`

C

`CH_(3)CH_(2)NHCH_(3)`

D

`(CH_(3))3)N`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the compound (X) with the molecular formula C₃H₉N that reacts with benzenesulphonyl chloride to form a solid insoluble in alkali, we can follow these steps: ### Step 1: Analyze the Molecular Formula The molecular formula C₃H₉N indicates that the compound contains three carbon atoms, nine hydrogen atoms, and one nitrogen atom. This suggests that the compound could be an amine. **Hint:** Look at the structure and possible types of amines that fit the molecular formula. ### Step 2: Identify the Type of Amine Given that the product formed from the reaction with benzenesulphonyl chloride is insoluble in alkali, it implies that the nitrogen atom in compound (X) does not have any hydrogen atoms attached to it after the reaction. This suggests that compound (X) is a secondary amine, as primary amines would still have one hydrogen attached to nitrogen. **Hint:** Remember the characteristics of primary, secondary, and tertiary amines. ### Step 3: Propose the Structure of Compound (X) A secondary amine can be represented as R₂NH, where R can be any alkyl group. For C₃H₉N, a suitable structure would be N-ethyl-N-methylamine, which can be written as: - CH₃-CH₂-NH-CH₃ This structure accounts for three carbon atoms and fits the molecular formula. **Hint:** Try drawing the structure to visualize the bonding and verify the molecular formula. ### Step 4: Reaction with Benzenesulphonyl Chloride When N-ethyl-N-methylamine reacts with benzenesulphonyl chloride (C₆H₅SO₂Cl), it forms N-ethyl-N-methyl-benzenesulphonamide. The reaction can be represented as: - CH₃-CH₂-NH-CH₃ + C₆H₅SO₂Cl → CH₃-CH₂-N(SO₂C₆H₅)-CH₃ + HCl The product formed is a sulphonamide which is solid and insoluble in alkali. **Hint:** Consider how the reaction changes the solubility properties of the amine. ### Step 5: Conclusion Thus, the compound (X) is identified as N-ethyl-N-methylamine, which is a secondary amine. **Final Answer:** The compound (X) is a secondary amine, specifically N-ethyl-N-methylamine.
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VMC MODULES ENGLISH-AMINES-PRACTICE EXERCISE:
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