Ethylamine can be obtaine by

Options

A. Action of `NH_(3)` on ethyl iodide
B. Action of `NH_(3)` on ethyl alcohol
C. Both 1 and 2
D. None of the above

Answer

To obtain ethylamine (C2H5NH2), we can consider two methods based on the reactions described. Here’s a step-by-step breakdown:

### Method 1: Reaction of Ethyl Iodide with Ammonia

1. **Starting Materials**: Ethyl iodide (C2H5I) and ammonia (NH3).
2. **Reaction**: When ethyl iodide reacts with ammonia, a nucleophilic substitution occurs.
- The ammonia acts as a nucleophile, attacking the carbon atom in ethyl iodide, which is bonded to the iodine atom.
3. **Products**: The reaction produces ethylamine (C2H5NH2) and hydrogen iodide (HI).
- The balanced equation for this reaction is:
\[ C2H5I + NH3 \rightarrow C2H5NH2 + HI \]

### Method 2: Reaction of Ethyl Alcohol with Ammonia

1. **Starting Materials**: Ethyl alcohol (C2H5OH) and ammonia (NH3).
2. **Reaction**: When ethyl alcohol reacts with ammonia, it undergoes a process where water is eliminated.
- The ammonia reacts with the hydroxyl group (–OH) of ethyl alcohol, leading to the formation of ethylamine and water.
3. **Products**: The reaction produces ethylamine (C2H5NH2) and water (H2O).
- The balanced equation for this reaction is:
\[ C2H5OH + NH3 \rightarrow C2H5NH2 + H2O \]

### Conclusion

Both methods yield ethylamine. Therefore, ethylamine can be obtained by:
- **Option A**: The reaction of ammonia with ethyl iodide.
- **Option B**: The reaction of ammonia with ethyl alcohol.

Thus, the correct answer is **C: both A and B**.

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