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Reduction of nitroalkanes in netural med...

Reduction of nitroalkanes in netural medius `(e.g. Zn+NH_(3)Cl)` forms mainly:

A

`R-NH_(2)`

B

`R-NHOH`

C

`R-N=N-Cl`

D

All of these

Text Solution

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The correct Answer is:
To solve the question regarding the reduction of nitroalkanes in a neutral medium, we can follow these steps: ### Step 1: Understand the Reactants We are dealing with nitroalkanes, which have the general structure R-NO2, where R is an alkyl group. The reduction process involves converting the nitro group (-NO2) into an amine group (-NH2) or other derivatives. ### Step 2: Identify the Reducing Agent In this case, the reducing agent is zinc (Zn) in the presence of ammonium chloride (NH3Cl) in a neutral medium. This combination is known to facilitate the reduction of nitro compounds. ### Step 3: Analyze the Reaction Conditions The reaction is taking place in a neutral medium. This is important because the pH of the medium can influence the products formed during the reduction process. In a neutral medium, nitroalkanes typically do not undergo complete reduction to amines. ### Step 4: Determine the Main Product When nitroalkanes are reduced in a neutral medium, the main product formed is an intermediate known as an alkylhydroxylamine (R-NH-OH). This is due to the partial reduction of the nitro group. ### Step 5: Conclude the Answer Therefore, the main product formed from the reduction of nitroalkanes in a neutral medium using zinc and ammonium chloride is R-NH-OH (alkylhydroxylamine). ### Final Answer The main product formed is R-NH-OH (alkylhydroxylamine). ---
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