When chlorobenzene is treated with `NH_(3)` in presence of `Cu_(2)O` in xylene is 570 K. The product obtained is

Options

A. Benzylamine
B. Diazonium salt
C. Schiff's base
D. Aniline

Answer

To solve the problem of what product is obtained when chlorobenzene is treated with ammonia (NH₃) in the presence of copper(I) oxide (Cu₂O) in xylene at 570 K, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants and Conditions**:
- The reactants are chlorobenzene (C₆H₅Cl) and ammonia (NH₃).
- The reaction occurs in the presence of copper(I) oxide (Cu₂O) and xylene at a temperature of 570 K.

2. **Understand the Reaction Mechanism**:
- The reaction involves nucleophilic substitution where the ammonia acts as a nucleophile and replaces the chlorine atom in chlorobenzene.
- The presence of Cu₂O facilitates the reaction by providing a suitable environment for the nucleophilic attack.

3. **Write the Balanced Reaction**:
- The balanced chemical equation for the reaction can be written as:
\[ 2 \text{C}_6\text{H}_5\text{Cl} + 2 \text{NH}_3 \xrightarrow{\text{Cu}_2\text{O}, 570 \text{K}} 2 \text{C}_6\text{H}_5\text{NH}_2 + \text{Cu}_2\text{Cl}_2 + 2 \text{H}_2\text{O} \]
- This indicates that two moles of chlorobenzene react with two moles of ammonia to produce two moles of aniline (C₆H₅NH₂), along with copper(I) chloride (Cu₂Cl₂) and water (H₂O).

4. **Identify the Product**:
- The primary product formed in this reaction is aniline (C₆H₅NH₂), which is the amine derived from chlorobenzene.

5. **Conclusion**:
- Therefore, the product obtained from the reaction of chlorobenzene with ammonia in the presence of Cu₂O at 570 K is aniline (C₆H₅NH₂).

### Final Answer:
The product obtained is **aniline (C₆H₅NH₂)**.

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