The refluxing of `(CH_3)_2NCOCH_3` with acid gives

Options

A. `(CH_(3))_(2)NH+CH_(3)COOH`
B. `(CH_(3))_(2)NCOOH+CH_(4)`
C. `2CH_(3)OH+CH_(3)CONH_(2)`
D. `2CH_(3)NH_(2)+CH_(3)COOH`

Answer

To solve the problem of what happens when `(CH₃)₂NCOCH₃` (dimethylacetamide) is refluxed with acid, we can follow these steps:

### Step 1: Identify the Reactants
The compound `(CH₃)₂NCOCH₃` is dimethylacetamide, which is an amide. When it is refluxed with an acid, we need to consider the possible reactions that can occur.

**Hint:** Look for the functional groups present in the compound and the nature of the acid.

### Step 2: Understand the Reaction with Acid
Refluxing dimethylacetamide with an acid can lead to hydrolysis. In the presence of a strong acid, the amide can be converted into a carboxylic acid and an amine.

**Hint:** Recall the general reaction of amides with acids, which typically results in the formation of a carboxylic acid and an amine.

### Step 3: Write the Reaction
The hydrolysis of dimethylacetamide can be represented as follows:

\[ (CH₃)₂NCOCH₃ + H₂O \xrightarrow{H^+} CH₃COOH + (CH₃)₂NH \]

In this reaction, dimethylacetamide reacts with water (in the presence of acid) to produce acetic acid (CH₃COOH) and dimethylamine ((CH₃)₂NH).

**Hint:** Make sure to balance the equation and identify all products formed.

### Step 4: Identify the Products
From the reaction, we can see that the products formed are:
1. Dimethylamine, \((CH₃)₂NH\)
2. Acetic acid, \(CH₃COOH\)

**Hint:** Verify the structure of the products to ensure they match the expected functional groups.

### Conclusion
Thus, the refluxing of `(CH₃)₂NCOCH₃` with acid gives dimethylamine and acetic acid.

### Final Answer
The products are:
- Dimethylamine \((CH₃)₂NH\)
- Acetic acid \(CH₃COOH\)

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