Benzldehyde condenses with N, N-dimethylaniline in presence of anhydrous `ZnCl_2` to give

Options

A. Michler's ketone
B. Azo dye
C. Malachite green
D. Butter yellow

Answer

To solve the problem of what product is formed when benzaldehyde condenses with N,N-dimethylaniline in the presence of anhydrous ZnCl2, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are:
- Benzaldehyde (C₆H₅CHO)
- N,N-Dimethylaniline (C₆H₅N(CH₃)₂)

### Step 2: Understand the Reaction Conditions
The reaction occurs in the presence of anhydrous ZnCl₂, which acts as a Lewis acid. This facilitates the condensation reaction by activating the carbonyl group of benzaldehyde.

### Step 3: Mechanism of the Reaction
1. **Formation of the Imine**: The nitrogen atom in N,N-dimethylaniline attacks the carbonyl carbon of benzaldehyde. This forms a tetrahedral intermediate.
2. **Proton Transfer**: A proton transfer occurs, leading to the formation of an imine (C=N) bond and the release of water.
3. **Formation of the Final Product**: The final product will be a compound where the imine is further stabilized by the presence of the dimethyl groups.

### Step 4: Write the Product Structure
The product formed from this reaction is known as **Malachite Green**. Its structure can be represented as:
- C₆H₅CH(C₆H₄N(CH₃)₂)₂

### Step 5: Conclusion
Thus, the product formed from the condensation of benzaldehyde with N,N-dimethylaniline in the presence of anhydrous ZnCl₂ is **Malachite Green**.

### Final Answer
The correct product is **Malachite Green**.

---