Solve `intsin2x.sin3xdx`

Explanation

To solve the integral \( \int \sin 2x \sin 3x \, dx \), we can use a trigonometric identity to simplify the product of the sine functions into a sum. Here’s a step-by-step solution:

### Step 1: Set up the integral
Let
\[ I = \int \sin 2x \sin 3x \, dx \]

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