The original length of wire is `(153.7 pm 0.6) cm`. It is streched to `(155.3 pm 0.2)` cm. Calculate the elongation in the wire with error limits.

Explanation

To solve the problem of calculating the elongation in the wire with error limits, we can follow these steps:

### Step 1: Identify the lengths and their uncertainties
- The original length of the wire, \( L_1 = 153.7 \, \text{cm} \) with an uncertainty of \( \Delta L_1 = 0.6 \, \text{cm} \).
- The stretched length of the wire, \( L_2 = 155.3 \, \text{cm} \) with an uncertainty of \( \Delta L_2 = 0.2 \, \text{cm} \).

### Step 2: Calculate the elongation
The elongation \( L \) in the wire is given by the difference between the stretched length and the original length:
...