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Two resistances R(1) = 100 +- 3 Omega an...

Two resistances `R_(1) = 100 +- 3 Omega and R_(2) = 200 +- 4 Omega` are connected in series . Find the equivalent resistance of the series combination.

A

`300 pm 5Ohm`

B

`300 pm 7Ohm`

C

`300pm 9 Ohm`

D

`300 pm 3Ohm`

Text Solution

Verified by Experts

The correct Answer is:
B
The equivalent resistance of series combination `R=R_(1)+R_(2)=(100 pm 3)ohm+(200pm 4)ohm=300pm 7ohm`
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