A substance having mass 5.74 g occupies a volume of `1.2cm^3.` Caluclate its density with due regard to significant digits.

Options

A. `4.7gcm^(-3)`
B. `4.8gcm^(-3)`
C. `4.5gcm^(-3)`
D. `4.6gcm^(-3)`

Answer

B

Explanation

Mass, m = 5.74g, volume `v=1.2cm^(3)` density, `d=(m)/(v)=(5.74g)/(1.2cm^(3))`
5.74 has three significant digits and 1.2 has two significant digits so, no need for rounding off.
`therefore d=(5.74)/(1.2)=4.78333`
This is to be rounded off to two significant digits. The density of the given substance `4.783=4.8gcm^(-3)`