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If X=(a^(3)b^(2))/(sqrtc) and percentage...

If `X=(a^(3)b^(2))/(sqrtc)` and percentage changes in a, b and c are `2%` increase, `1%` decrease and `2%` decrease respectively then percentage increase or decrease in X is

A

`5%` increase

B

`5%` decrease

C

`9%` increase or decrease

D

`9%` increase

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the percentage change in \( X \) given the formula: \[ X = \frac{a^3 b^2}{\sqrt{c}} \] We also know the percentage changes in \( a \), \( b \), and \( c \): - \( a \): 2% increase - \( b \): 1% decrease - \( c \): 2% decrease ### Step 1: Write the formula for percentage change in \( X \) Using the error propagation formula for functions of multiple variables, we can express the percentage change in \( X \) as: \[ \frac{\Delta X}{X} = 3 \frac{\Delta a}{a} + 2 \frac{\Delta b}{b} - \frac{1}{2} \frac{\Delta c}{c} \] ### Step 2: Substitute the percentage changes Now we substitute the given percentage changes into the formula: - For \( a \): \( \frac{\Delta a}{a} = \frac{2}{100} = 0.02 \) (since it's an increase) - For \( b \): \( \frac{\Delta b}{b} = -\frac{1}{100} = -0.01 \) (since it's a decrease) - For \( c \): \( \frac{\Delta c}{c} = -\frac{2}{100} = -0.02 \) (since it's a decrease) Substituting these values into the formula gives: \[ \frac{\Delta X}{X} = 3(0.02) + 2(-0.01) - \frac{1}{2}(-0.02) \] ### Step 3: Calculate each term Now, calculate each term: 1. \( 3(0.02) = 0.06 \) 2. \( 2(-0.01) = -0.02 \) 3. \( -\frac{1}{2}(-0.02) = 0.01 \) ### Step 4: Combine the results Now, combine the results: \[ \frac{\Delta X}{X} = 0.06 - 0.02 + 0.01 = 0.05 \] ### Step 5: Convert to percentage To express this as a percentage, we multiply by 100: \[ \Delta X \% = 0.05 \times 100 = 5\% \] ### Conclusion Since the result is positive, it indicates a percentage increase in \( X \). Therefore, the final answer is: \[ \text{Percentage increase in } X = 5\% \]
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