A particle moves along the x-axis in such a way that its x-co-ordinate varies with time as `x = 2 – 5t + 6t^(2)`.
The initial velocity and acceleration of particle will respectively be-

Options

A. `-5,12`
B. `0,12`
C. `-5,0`
D. `-5,-12`

Explanation

To solve the problem, we need to find the initial velocity and acceleration of the particle whose position as a function of time is given by the equation:

\[ x(t) = 2 - 5t + 6t^2 \]

### Step 1: Find the velocity function
The velocity \( v(t) \) of the particle is the first derivative of the position function \( x(t) \) with respect to time \( t \).

\[
...