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The relation between time t and distance...

The relation between time t and distance `x t= ax^(2) +bx` is , where a and b are constants. The acceleration is:

A

`2av^(3)`

B

`-2av^(2)`

C

`2av^(2)`

D

`av^(2)`

Text Solution

Verified by Experts

`(dt)/(dx) =2ax +p`
`? V=(1)/(2ax+p)`
`a=(dv)/(dt)=(dv)/(dx) cdot (dx)/(dt)`
`a=(vdv)/(dx) =(-v(2a))/((2ax+p)^(2))=-2av xx v^(2) =-2av^(3)`
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