A particle is projected vertically upward with initial velocity `25" ms"^(–1)`. During third second of its motion, which of the following statement is correct ?

Options

A. displacement of the particle is 30 m
B. distance covered by the particle is 30 m
C. distance covered by the particle is 2.5 m
D. None of these

Explanation

To solve the problem of a particle projected vertically upwards with an initial velocity of \(25 \, \text{m/s}\), we need to analyze its motion during the third second. We will calculate the displacement and distance covered during this specific time interval.

### Step-by-Step Solution:

1. **Identify the Variables:**
- Initial velocity (\(u\)) = \(25 \, \text{m/s}\)
- Acceleration due to gravity (\(g\)) = \(10 \, \text{m/s}^2\) (acting downwards)
- We need to find the displacement during the third second, which is from \(t = 2 \, \text{s}\) to \(t = 3 \, \text{s}\).
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