Home
Class 12
PHYSICS
A particle moves along a straight line s...

A particle moves along a straight line such that its displacement at any time t is given by `s = (t^(3)-6t^(2)+3t +4)m`
The velocity when the acceleration is zero, is

A

`3" ms"^(-1)`

B

`-12" ms"^(-1)`

C

`42" ms"^(-1)`

D

`-9" ms"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • Motion in Straight Line

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE-C|10 Videos

  • Motion in Straight Line

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE-D|10 Videos

  • Motion in Straight Line

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE-A|11 Videos

  • MOTION IN A STRAIGHT LINE & PLANE

    VMC MODULES ENGLISH|Exercise IMPECCABLE|52 Videos

  • Motion in Two Dimensions

    VMC MODULES ENGLISH|Exercise MCQ|2 Videos

Similar Questions

Explore conceptually related problems

A particle moves along a staight line such that its displacement at any time t is given by s=t^3-6t^2+3t+4m . Find the velocity when the acceleration is 0.

A particle moves along a straight line such that its displacement at any time t is given by s = 3t^(3)+7t^(2)+14t + 5 . The acceleration of the particle at t = 1s is

A particle is moving in a straight line such that its distance s at any time t is given by s=(t^4)/4-2t^3+4t^2-7. Find when its velocity is maximum

A particle is moving in a straight line such that its distance s at any time t is given by s=(t^4)/4-2t^3+4t^2-7. Find when its velocity is maximum and acceleration minimum.

For a particle moving in a straight line, the displacement of the particle at time t is given by S=t^(3)-6t^(2) +3t+7 What is the velocity of the particle when its acceleration is zero?

For a particle moving in a straight line, the displacement of the particle at time t is given by S=t^(3)-6t^(2) +3t+7 What is the velocity of the particle when its acceleration is zero?

A particle is moving in a straight line. Its displacement at time t is given by s(I n m)=4t^(2)+2t , then its velocity and acceleration at time t=(1)/(2) second are

A particle moves along a straight line and its position as a function of time is given by x = t6(3) - 3t6(2) +3t +3 , then particle

The distances moved by a particle in time t seconds is given by s=t^(3)-6t^(2)-15t+12 . The velocity of the particle when acceleration becomes zero, is

For a particle moving along a straight line, the displacement x depends on time t as x = alpha t^(3) +beta t^(2) +gamma t +delta . The ratio of its initial acceleration to its initial velocity depends