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A train accelerates from rest at a const...

A train accelerates from rest at a constant rate a for time `t_(1)`and then it retards at the constant rate `b` for time `t_(2)` then comes to rest. Find the ratio `t_(1)`/`t_(2)`.

A

`(x_(1))/(x_(2))=(a)/(p)=(t_(1))/(t_(2))`

B

`(x_(1))/(x_(2))=(p)/(a) =(t_(1))/(t_(2))`

C

`(x_(1))/(x_(2))=(a)/(p) =(t_(2))/(t_(1))`

D

`(x_(1))/(x_(2))=(p)/(a) =(t_(2))/(t_(1))`

Text Solution

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The correct Answer is:
B
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