Home
Class 12
PHYSICS
A particle is moving around a circular p...

A particle is moving around a circular path with uniform angular speed (x) . The radius of the circular path is (r). The acceleration of the particle is:

A

`(x2)/(r )`

B

`(x)/(r )`

C

`vx`

D

`vr`

Text Solution

AI Generated Solution

The correct Answer is:
To find the acceleration of a particle moving in a circular path with uniform angular speed, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Motion**: The particle is moving in a circular path with uniform angular speed \( x \). This means that the angular speed does not change over time. 2. **Identify Types of Acceleration**: In circular motion, there are two types of acceleration: - **Tangential Acceleration (\( a_t \))**: This is due to the change in the speed of the particle along the circular path. - **Radial Acceleration (\( a_r \))**: This is directed towards the center of the circular path and is responsible for changing the direction of the velocity vector. 3. **Determine Tangential Acceleration**: Since the particle is moving with uniform angular speed, the linear speed \( V \) is constant. Therefore, the tangential acceleration \( a_t \) is: \[ a_t = \frac{dV}{dt} = 0 \] 4. **Calculate Radial Acceleration**: The radial acceleration can be calculated using the formula: \[ a_r = \frac{V^2}{r} \quad \text{or} \quad a_r = r \omega^2 \] where \( \omega \) is the angular speed. In this case, \( \omega = x \). 5. **Relate Linear Velocity to Angular Speed**: The linear velocity \( V \) can be expressed in terms of the radius \( r \) and angular speed \( x \): \[ V = r \cdot x \] 6. **Substitute for Radial Acceleration**: Using the relationship \( V = r \cdot x \) in the radial acceleration formula: \[ a_r = \frac{(r \cdot x)^2}{r} = \frac{r^2 \cdot x^2}{r} = r \cdot x^2 \] 7. **Final Result**: Since the tangential acceleration is zero, the total acceleration \( a \) of the particle is equal to the radial acceleration: \[ a = a_r = r \cdot x^2 \] ### Conclusion: The acceleration of the particle moving around a circular path with uniform angular speed \( x \) and radius \( r \) is given by: \[ \text{Acceleration} = r \cdot x^2 \]
Promotional Banner

Topper's Solved these Questions

  • Motion in Straight Line

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE-J|10 Videos
  • Motion in Straight Line

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE-H|10 Videos
  • MOTION IN A STRAIGHT LINE & PLANE

    VMC MODULES ENGLISH|Exercise IMPECCABLE|52 Videos
  • Motion in Two Dimensions

    VMC MODULES ENGLISH|Exercise MCQ|2 Videos

Similar Questions

Explore conceptually related problems

A particle revolves round a circular path with uniform speed. The acceleration of the particle is

A particle moves in a circular path with a uniform speed. Its motion is

A particle is moving along a circular path of radius 5 m with a uniform speed 5ms^(-1) . What will be the average acceleration when the particle completes half revolution?

A particle is moving on a circular path with constant speed, then its acceleration will be constant in

A body is moving in a circular path with a constant speed. It has .

A body is moving in a circular path with a constant speed. It has .

A particle is moving along a circular path with a constant speed 10 ms^-1 .What is the magnitude of the change in velocity of the particle ,when it moves through an angle of 60^@ around the center of the circle ?

A particle is revoiving in a circular path of radius 25 m with constant angular speed 12 rev/min. then the angular acceleration of particle is

A particle of mass m is moving on a circular path of radius r with uniform speed v , rate of change of linear momentum is

A particle is moving on a circular path with a constant speed v . Its change of velocity as it moves from A to B is: