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The radius of the circular path of a par...

The radius of the circular path of a particle is doubled but its frecuency of rotation remains unchanged . If the initial centripetal force be F, then the final centripetal force will be

A

(a) F

B

(b)`(F)/(2)`

C

(c)4F

D

(d)2F

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will analyze the relationship between the centripetal force, radius, and frequency of rotation. ### Step-by-Step Solution: 1. **Understanding Centripetal Force**: The centripetal force \( F \) acting on a particle moving in a circular path is given by the formula: \[ F = m \cdot a_c \] where \( a_c \) is the centripetal acceleration. The centripetal acceleration can be expressed in terms of the radius \( r \) and angular velocity \( \omega \): \[ a_c = \frac{v^2}{r} = r \cdot \omega^2 \] Thus, the centripetal force can also be expressed as: \[ F = m \cdot r \cdot \omega^2 \] 2. **Initial Conditions**: Let the initial radius be \( r_1 \) and the initial centripetal force be \( F \). Therefore, we can write: \[ F = m \cdot r_1 \cdot \omega^2 \] 3. **Doubling the Radius**: According to the problem, the radius is doubled, so the new radius \( r_2 \) is: \[ r_2 = 2 \cdot r_1 \] 4. **Frequency Remains Unchanged**: Since the frequency of rotation remains unchanged, the angular velocity \( \omega \) also remains constant. Thus, we have: \[ \omega_2 = \omega_1 = \omega \] 5. **Calculating the New Centripetal Force**: The new centripetal force \( F_2 \) when the radius is doubled can be expressed as: \[ F_2 = m \cdot r_2 \cdot \omega^2 \] Substituting \( r_2 \): \[ F_2 = m \cdot (2 \cdot r_1) \cdot \omega^2 \] This simplifies to: \[ F_2 = 2 \cdot (m \cdot r_1 \cdot \omega^2) \] 6. **Relating to Initial Centripetal Force**: From our initial condition, we know that: \[ F = m \cdot r_1 \cdot \omega^2 \] Therefore, substituting this into our expression for \( F_2 \): \[ F_2 = 2 \cdot F \] 7. **Final Result**: The final centripetal force when the radius is doubled while keeping the frequency constant is: \[ F_2 = 2F \] ### Conclusion: The final centripetal force will be \( 2F \). ---
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