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A particle of mass m is projected with a...

A particle of mass `m` is projected with a velocity `V`. making an angle of `45^@` with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle at its maximum height h is

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`L_0=mvr_bot` At the highest point, V=speed=`V_0cos45^@` `r_bot=h=(V_(0)^(2)sin^2 45^@)/(2g)` `L_0=m((V_0)/sqrt2)((V_(0)^(2))/(4g))=(mV_(0)^(3))/(4sqrt2g)`.
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