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The cue stick hits a cue ball horizontal...

The cue stick hits a cue ball horizontally a distance `x` above the centre of the ball. Find the value of `x` for which the cue ball will instantaneously roll without slipping. Calculate the answer in terms of the radius `R` of the ball.

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The horizontal force creates a linear impulse and angular impulse.`I=intFdt``J=inttaudt=lh`Linear impulse = change in linear momentum `rArr I=MV_(Cm)-0`..(i) Angular impulse about CM = change in angular momentum `J=lh=2/5mr^2omega-0`..(ii)Dividing (ii) and(i) we get `h=(2Mr^2omega)/(5MV_(CM))` Using `V_(CM)=romega``h=R/5R`.
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