If the moment of inertia of a disc about...

If the moment of inertia of a disc about an axis tangential and parallel to its surface be I, then what will be the moment of inertia about the axis tangential but perpendicular to the surface?

`6/5I`

`3/4I`

`3/2I`

`5/4I`

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Verified by Experts

The correct Answer is:

`I_1=(1/4mr^2)+mr^2=(5mr^2)/4=I` `rArrI_2=1/2mr^2+mr^2=3/2mr^2=(6I)/5`

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