A uniform rod of mass `m` and length `l` rotates in a horizontal plane with an angular velocity `omega` about a vertical axis passing through one end. The tension in the rod at a distance x from the axis is

Options

A. `1/2momega^2x`
B. `1/2momega^2x^2/l`
C. `1/2momega^2(1-1/2)`
D. `1/(2l).momega^2[l^2-x^2]`

Answer

4

Explanation

P is the CM of part II.`rArrA_(CM)=omega^2(OP)=omega^2((l+x)/2)``rArrT(x)=m_2omega^2((l+x)/2)` where `m_2=m/l(l-x)``rArrT(x)=(momega^2)/(2l)(l^2-x^2)`