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Moment of inertia of a uniform circular ...

Moment of inertia of a uniform circular disc about a diameter is `I`. Its moment of inertia about an axis perpendicular to its plane and passing through a point on its rim will be

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Moment of inertia of disc about a diameter=`1/4MR^2`=I(given) `becauseMR^2=4I`Now moment of inertia of disc about an axis perpendicular to its plane and passing through a point on its rim =`3/2MR^2=3/2(4I)=6I`.
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Knowledge Check

  • One quarter sector is cut from a uniform circular disc of radius R. The sector has mass M. IT is made to rotate about a line perpendicular to its plane and passing through the centre of the original disc. Its moment of inertia about the axis of rotation is

    A
    `MR^(2)//2`
    B
    `MR^(2)//4`
    C
    `MR^(2)//8`
    D
    `sqrt(2)MR^(2)`

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