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A fly wheel of M.I. 0.32 kg m^(2) is rot...

A fly wheel of M.I. `0.32 kg m^(2)` is rotated steadily at 120 rad/s by 50 w electric motor. Then the value of the frictional couple opposing rotation is,

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Kinetic energy `K_R=1/2Iomega^2=1/2(0.32)(120)^2=2304J`.
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