If each resistance in the figure is of 9...

If each resistance in the figure is of `9Omega` then reading of ammeter is

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The correct Answer is:

Main current through the battery i = `(9)/(1)`=9A Current through each resistance will be 1A and only 5 resistances on the right side of ammeter contributes for passing current through the ammeter. So reading of ammeter will be 5A.

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