Home
Class 12
PHYSICS
In the figure, the potentiometer wire of...

In the figure, the potentiometer wire of length `l = 100 cm` and resistance `9 Omega` is joined to a cell of emf cell of emf `E_(2) = 5 V` and internal resistance `r_(2) = 2 V` is connected as shown. The galvanometer is show no deflection when the length AC is

A

50cm

B

55.55cm

C

52.67cm

D

54.33cm

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • CURRENT ELECTRICITY

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE-F|10 Videos
  • CURRENT ELECTRICITY

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE-D|9 Videos
  • CAPACITORS

    VMC MODULES ENGLISH|Exercise JEE Advance ( Archive ) LEVEL 48|1 Videos
  • DC CIRCUIT

    VMC MODULES ENGLISH|Exercise JEE ADVANCED ARCHIVE|68 Videos

Similar Questions

Explore conceptually related problems

In the figure the potentiometer wire AB of length L and resistance 9 r is joined to the cell D of e.m.f epsilon and internal resistance r. The emf of cell C is epsilon/2 and its internal resistance is 2r.The galvanometer G will show on deflection when the length AJ is

A potentiometer wire AB having length L and resistance 12 r is joined to a cell D of emf epsi//2 and internal resistance 3r is connected. The length AJ at which the galvanometer as shown in fig. Shows no deflection is :

A potentiometer consists of a wire of length 4 m and resistance 10Omega . It is connected to a cell of emf 2V.The potential gradient of the wire is

Find the current drawn from a cell of emf 2 V and internal resistance 2 Omega connected to the network given below.

Eight cells marked 1 to 8, each of emf 5 V and internal resistance 0.2 Omega are connected as shown. What is the reading of ideal voltmeter ?

An accumulator of emf 2 V and negligible internal resistance is connected across a uniform wire of length 10 m and resistance 30 Omega The appropriate terminals of a cell of emf 1.5 V and internal resistance 1 Omega is connected to one end of the wire and the other terminal of the cell is connected through a sensitive galvanometer to a slider on the wire. What is the length of the wire that will be required to produce zero deflection of the galvanometer? How will the balancing length change? (a) When a coil of resistance 5Omega is placed in series with the accumulator. (b) The cell of 1.5 V is shunted with 5 Omega resistor?

A battery of emf E_(0)=12V is connected across a 4m long uniform wire having resistance 4Omega//m . The cells of small emfs e_(1)=2V and e_(2)=4V having internal resistance 2Omega and 6Omega respectively, are connected as shown in the figure. If galvanometer shows no deflection at the point N, the distance of point N from the point A is equal to

In given figure, the potentiometer wire AB has a resistance of 5 Omega and length 10 m . The balancing length AM for the emf of 0.4 V is

The wire of potentiometer has resistance 4 Omega and length 1m. It is connected to a cell of e.m.f. 2V and internal resistance 1 Omega . The current flowing through the potentiometer wire is

A battery of emf E_(0) = 12 V is connected across a 4 m long uniform wire having resistance (4 Omega)/(m) . The cells of small emfs epsilon_(1) = 2 V and epsilon_(2) - 4 V having internal resistance 2 Omega and 6 Omega respectively, are connected as shown in the figure. If galvanometer shows no deflection at the point N , the distance of point N from teh point A is equal to