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An electric bulb, marked 40 W and 200 V,...

An electric bulb, marked `40 W` and `200 V`, is used in a circuit of supply voltage `100 V`. Now its power is

A

10w

B

20W

C

40W

D

100W

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the power consumed by the electric bulb when it is supplied with a voltage of 100 V, given that it is rated at 40 W and 200 V. ### Step-by-Step Solution: 1. **Understand the given values**: - Rated Power (P1) = 40 W - Rated Voltage (V1) = 200 V - Supply Voltage (V2) = 100 V 2. **Calculate the resistance of the bulb**: The resistance (R) of the bulb can be calculated using the rated power and voltage: \[ P1 = \frac{V1^2}{R} \implies R = \frac{V1^2}{P1} \] Substituting the values: \[ R = \frac{(200)^2}{40} = \frac{40000}{40} = 1000 \, \Omega \] 3. **Calculate the power at the new voltage (V2 = 100 V)**: Using the formula for power: \[ P2 = \frac{V2^2}{R} \] Substituting the values: \[ P2 = \frac{(100)^2}{1000} = \frac{10000}{1000} = 10 \, W \] 4. **Conclusion**: The power consumed by the bulb when supplied with 100 V is 10 W. ### Final Answer: The power of the bulb when used in a circuit with a supply voltage of 100 V is **10 W**. ---
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