A proton of mass `1.67 xx 10^(-27)` kg and charge `1.6 xx 10^(-19)`C is shot a uniform magnetic field, and perpendicular to the field with a velocity `5 xx 10^(6) m//s`. If the magnetic induction of the field is 1 tesla, find
(i) The radius of the circular path

Explanation

To find the radius of the circular path of a proton moving in a magnetic field, we can use the formula for the radius \( r \) of the circular motion of a charged particle in a magnetic field, which is given by:

\[ r = \frac{mv}{qB} \]

Where:
- \( m \) is the mass of the proton,
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