A horizontal rod of mass `10g` and length `10cm` is placed on a smooth plane inclined at an angle of `60^@` with the horizontal with the length of the rod parallel to the edge of the inclined plane. A uniform magnetic field induction B is applied vertically downwards. If the current through the rod is `1*73ampere`, the value of B for which the rod remains stationary on the inclined plane is

Explanation

To solve the problem step by step, we will analyze the forces acting on the rod and apply the necessary physics principles.

### Step 1: Identify the Forces Acting on the Rod
The rod is subjected to two main forces:
1. The gravitational force acting downwards, \( F_g = mg \).
2. The magnetic force acting perpendicular to the current and the magnetic field.

### Step 2: Calculate the Gravitational Force
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