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Two particles, each of mass m and charge q, are attached to the two ends of a light rigid rod of length 2R. The rod is rotated at constant angular speed about a perpendicular axis passing through its centre. The ratio of the magnitudes of the magnetic moment of the system and its angular momentum about the centre of the rod is:

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Verified by Experts

Rotating charge 2q creates a current I where
`I=charge/timeperiod` =`2q/ 2pi//omega`
`L=2mR^(2)omega` , `M=IA=(q omega/pi)/pi R^(2)`
Now,`M/L=qr^(2)omega/2mR^(2)omega=q/2m`
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