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In the magnetic meridian of a certain pl...

In the magnetic meridian of a certain place, the horizontal component of the earth’s magnetic field is 0.26G and the dip angle is `60^(@)`. What is the magnetic field of the arth at this location?

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It is given that `H_(E)`=0.26G
`cos60^(@)=H_(E)/B_(E)`
`B_(E)=H_(E)/cos60^(@)=0.26/(1//2)=0.52G`
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VMC MODULES ENGLISH-MOVING CHARGES & MAGNETISM -Illustration
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