A dip circle is tpo that its needle moves freely in the magnetic meridian. In this position, the angle of dip is `40^(@)`. Now, the dip circle is rotated so that the plane in which the needle moves makes an angle of `30^(@)` with the magnetic meridian. In this position the needle will dip by an angle.

Options

A. `40^(@)`
B. `30^(@)`
C. More than `40^(@)`
D. Less than `40^(@)`

Answer

3

Explanation

`tan theta =B_(v)/B_(H)` ……(i)
If apparent dip is `theta` then
`tan theta’=B’_(v)/B’_(H)=B_(v)/B_(H)xxsqrt(3)/2`
`tan theta ‘ =(2/sqrt(3))tan theta rArr tan theta ‘>tan theta rArr theta’= tantheta `