What is the net force on the rectangular coil

Options

A. `25 xx10^(-7)` N moving towards wire
B. `25 xx10^(-7)` N moving away from wire
C. `35 xx10^(-7)` N moving towards wire
D. `25 xx10^(-7)`N moving away from wire

Answer

1

Explanation

Force on sides BC and CD cancel each other.
Force on side AB
`F_(AB)=10^(-7)xx 2xx2xx1/2xx10^(-2) xx15xx10^(-2) = 3xx10^(-6)N`
Force on side CD
`F_(AB)=10^(-7)xx 2xx2xx1/12xx10^(-2) xx15xx10^(-2) = 0.5 xx10^(-6)N`
Hence net force on loop`=F_(AB)-F_(CD)=25xx10^(-7)`N (towards the wire).