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A vertical straight conductor carries a ...

A vertical straight conductor carries a current vertically upwards. A point `P` lies to the east of it at a small distance and another point `Q` lies to the west at the same distance. The magnetic field at `P` is

A

Greater than at Q

B

Same as at Q

C

Less than at Q

D

Greater or less than at Q depending upon the magnetic field strength

Text Solution

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The correct Answer is:
To solve the problem, we need to determine the magnetic field at point P, which is located to the east of a vertical straight conductor carrying current upwards, and compare it to the magnetic field at point Q, which is located to the west of the same conductor. ### Step-by-Step Solution: 1. **Understand the Setup**: - We have a vertical straight conductor carrying a current \( I \) in the upward direction. - Point \( P \) is located to the east of the conductor, and point \( Q \) is located to the west, both at the same distance \( R \) from the conductor. 2. **Use the Right-Hand Rule**: - To determine the direction of the magnetic field created by the current in the conductor, we can use the right-hand rule. - Point your thumb in the direction of the current (upwards), and curl your fingers around the conductor. Your fingers will point in the direction of the magnetic field lines. 3. **Determine the Magnetic Field at Point P**: - At point \( P \) (to the east), the magnetic field \( B_P \) will be directed into the page (or screen) based on the right-hand rule. 4. **Determine the Magnetic Field at Point Q**: - At point \( Q \) (to the west), the magnetic field \( B_Q \) will be directed out of the page (or screen) based on the right-hand rule. 5. **Calculate the Magnitude of the Magnetic Field**: - The magnitude of the magnetic field due to a long straight conductor at a distance \( R \) is given by the formula: \[ B = \frac{\mu_0 I}{2 \pi R} \] - Since both points \( P \) and \( Q \) are at the same distance \( R \) from the conductor, the magnitudes of the magnetic fields at both points will be equal: \[ B_P = B_Q = \frac{\mu_0 I}{2 \pi R} \] 6. **Conclusion**: - The magnitudes of the magnetic fields at points \( P \) and \( Q \) are equal, but their directions are opposite. Therefore, we can conclude that: \[ |B_P| = |B_Q| \] - The correct option is that the magnetic field at point \( P \) is equal in magnitude to the magnetic field at point \( Q \), but they have opposite directions.
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