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A circular coil 'A' has a radius R and t...

A circular coil 'A' has a radius R and the current flowing through it is I.Another circular coil 'B' has a radius 2R and if `2I` is the current flowing through it then the magnetic fields at the centre of the circular coil are in the ratio of

A

0.16736111111111

B

0.084027777777778

C

0.12569444444444

D

0.042361111111111

Text Solution

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The correct Answer is:
To find the ratio of the magnetic fields at the center of two circular coils, we can use the formula for the magnetic field at the center of a circular coil, which is given by: \[ B = \frac{\mu_0 I}{2R} \] where: - \( B \) is the magnetic field, - \( \mu_0 \) is the permeability of free space (a constant), - \( I \) is the current flowing through the coil, - \( R \) is the radius of the coil. ### Step 1: Calculate the magnetic field for coil A For coil A, we have: - Radius \( R_A = R \) - Current \( I_A = I \) Using the formula: \[ B_A = \frac{\mu_0 I_A}{2R_A} = \frac{\mu_0 I}{2R} \] ### Step 2: Calculate the magnetic field for coil B For coil B, we have: - Radius \( R_B = 2R \) - Current \( I_B = 2I \) Using the formula: \[ B_B = \frac{\mu_0 I_B}{2R_B} = \frac{\mu_0 (2I)}{2(2R)} = \frac{\mu_0 I}{2R} \] ### Step 3: Find the ratio of the magnetic fields Now, we can find the ratio of the magnetic fields \( \frac{B_A}{B_B} \): \[ \frac{B_A}{B_B} = \frac{\frac{\mu_0 I}{2R}}{\frac{\mu_0 I}{2R}} = 1 \] Thus, the ratio of the magnetic fields at the center of the two coils is: \[ B_A : B_B = 1 : 1 \] ### Conclusion The magnetic fields at the center of the two coils are equal, hence the ratio is \( 1 : 1 \).
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