Home
Class 12
PHYSICS
Two galvanometers A and B require 3 mA a...

Two galvanometers A and B require 3 mA and 6 mA respectively, to produce the same deflection of 10 divisions. Then,

A

A is more sensitive than B

B

B is more sensitive than A

C

A and B are equally sensitive

D

Sensitiveness of B is twice that of A

Text Solution

Verified by Experts

The correct Answer is:
1
Promotional Banner

Topper's Solved these Questions

  • MOVING CHARGES & MAGNETISM

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE-F|10 Videos

  • MOVING CHARGES & MAGNETISM

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE-G|10 Videos

  • MOVING CHARGES & MAGNETISM

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE-D|12 Videos

  • Motion in Two Dimensions

    VMC MODULES ENGLISH|Exercise MCQ|2 Videos

  • PROPERTIES OF MATTER

    VMC MODULES ENGLISH|Exercise JEE Advanced (Archive) Level - 2 (MATRIX MATCH TYPE)|1 Videos

Similar Questions

Explore conceptually related problems

Two galvanometers A and B require 3 mA and 5 mA respectively to produce the same deflection of i_(0) division. Then

In a galvanometer, a current of 1muA produces a deflection of 20 divisions. It has a resistance of 10Omega . If the galvanometer has 50 vivisions on its scale and a shunt of 2.5Omega . Is connected across the galvanometer, the maximum current that the Galvanometer can measure now is

A galvanometer has a resistance of 30 ohm and a current of 2 mA is needed to give a full scale deflection. What is the resistance needed and how is it to be connected to convert this galvanometer (a) Into an ammeter of 0.3 A range ? (b) Into a volmeter of 0.2 V range ?

A voltmeter which can measure 2 V isconstructed by using a galvanometer of resistance 12 Omega and that produces maximum deflection for the current of 2mA. Then the resistance R is

A galvanometer vaving 50 divisions provided with a variable shunt S is used to measure the current when conneted in series with a resistance of 90 Omega and a battery of internal resistance 10 Omega . It is observed that when the snt resistaces are 10 Omega & 70 Omega respectively, the deflection are respectively 9 and 30 dividions. What is the resistance of the galvanometer ? Further, if the full scale deflection of the galvanometer movement require 200 mA. find the emf of the cell.

A galvanometer of resistance 30Omega is connected to a battery of emf 2 V with 1970Omega resistance in series. A full scale deflection of 20 divisions is obtained in the galvanometer. To reduce the deflection to 10 divisions, the resistance in series required is

A galvanometer of resistance 40 Omega gives a deflection of 5 divisions per mA. There are 50 divisions on the scale. The maximum current that can pass through it when a shunt resistance of 2Omega is connected is

Deflection of galvanometer in the circuit is 71 divisions. A shunt of 15Omega is connected parallel to galvanometer and value of R is adjusted such that main current ramains the same. If the deflection in the galvanometer falls to 15 divisions then the resistance G of galvanometer in (in ohm)

The galvanometer shown in figure has resistance 50 Omega and current required for full scale deflection is 1mA. Find the resistance R_(1),R_(2) and required to convert to convert it into ammeter having ranges as indicated.

A galvanometer coil has a resistance of 15 Omega and the metre shows full scale deflection for a current of 4 mA. To convert the meter into a voltmeter of range 0 to 18 V, the required resistance is