The magnetic moment of atomic neon is

Options

A. (a)zero
B. (b)`(1//2)m_(B)`
C. (c)`m_(B)`
D. (d)`(3//2)m_(B)`

Answer

To find the magnetic moment of atomic neon, we can follow these steps:

### Step 1: Understand the nature of neon
Neon is a noble gas and is known to be diamagnetic. This means that it has no unpaired electrons, which results in a magnetic moment of zero.

### Step 2: Recall the definition of magnetic moment
The magnetic moment (μ) of an atom is generally given by the formula:
\[ \mu = \sqrt{n(n + 2)} \]
where \( n \) is the number of unpaired electrons.

### Step 3: Identify the number of unpaired electrons in neon
For neon (Ne), the electronic configuration is:
\[ 1s^2 2s^2 2p^6 \]
This shows that all the electrons are paired. Therefore, the number of unpaired electrons \( n = 0 \).

### Step 4: Calculate the magnetic moment
Using the formula for magnetic moment:
\[ \mu = \sqrt{n(n + 2)} \]
Substituting \( n = 0 \):
\[ \mu = \sqrt{0(0 + 2)} = \sqrt{0} = 0 \]

### Step 5: Conclusion
Since the magnetic moment of atomic neon is calculated to be zero, we conclude that the magnetic moment of atomic neon is:
\[ \mu = 0 \]

### Final Answer
The magnetic moment of atomic neon is 0.

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