Home
Class 12
PHYSICS
A coil of inductance 2 H and resistance ...

A coil of inductance `2 H` and resistance `10 Omega` are in a series circuit with an open key and a cell of constant `100 V` with negligible resistance. At time `i = 0`, the key is closed. Find
(a) the time constant of the circuit.
(b) the maximum steady current in the circuit.
(c) the current in the circuit at `f =1 s`.

Text Solution

Verified by Experts

The time constant iszeta=L/R = 5 x x10^(-3)s
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETIC INDUCTION & ALTERNATING CURRENT

    VMC MODULES ENGLISH|Exercise SOLVED EXAMPLES|24 Videos

  • ELECTROMAGNETIC INDUCTION & ALTERNATING CURRENT

    VMC MODULES ENGLISH|Exercise PRACTICE EXERCISE 1|10 Videos

  • DYNAMICS OF A PARTICLE

    VMC MODULES ENGLISH|Exercise JEE Advance (Archive) Level - II (SINGLE OPTION CORRECT TYPE )|31 Videos

  • ELECTROMAGNETIC INDUCTION & ALTERNATIVE CURRENT

    VMC MODULES ENGLISH|Exercise IMPECCABLE|52 Videos

Similar Questions

Explore conceptually related problems

Find time constant of the circuit when (a) S is closed . (b) S is open.

A capacitor of capacity 1muF is connected in a closed series circuit with a resistance or 10^(7) ohms, an open key and a cell of 2 V with negligible internal resistance : (i) When the key is switched on at time t=0, find, (a) The time constant for the circuit. (b) The charge on the capacitor at steady state. (c) Time taken to deposit charge equal to half of charge that will deposit at steady state. (ii) If after completely charging the capacitor, the cell is shorted by zero resistance at time t=0, find the charge on the capacitor at t=50 s. (Given : e^(-5)=6.73xx10^(-3), ln^(2)=0.693 )

A coil of self inductance 2.5 H and resistance 20 Omega is connected to a battery of emf 120 V having internal resistance of 5 Omega . Find : The time constant of the circuit

When a capacitor discharges through a resistance R, the time constant is tau and the maximum current in the circuit is i_0 . Then,

A coil with self inductance of 2.4H and resistance 12 Omega is suddenly switched across a 120V direct current supply of negligible internal resistance. Determine (i) the time constant of the coil and (ii) the final steady current

A coil of self inductance 2.5 H and resistance 20 Omega is connected to a battery of emf 120 V having internal resistance of 5 Omega . Find : The current in the circuit in steady state.

An inductor of 3H is connected to a battery of emf 6V through a resistance of 100 Omega . Calculate the time constant. What will be the maximum value of current in the circuit ?

In an LR circuit, current at t=0 is 20A . After 2s it reduced to 18A. The time constant of the circuit is (in second)

A condenser of capacity 1 mu F and a resistance 0.5 mega-ohm are connected in series with a DC supply of 2 V. The time constant of circuit is

The current in a discharging LR circuit without the battery drops from 2.0 A to 1.0A in 0.10 s. (a) find the time constant of the circuit. (b) if the inductance of the circuit is 4.0 H, what is its resistance?