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A 50 mH inductor is in series with a 10 ...

A 50 mH inductor is in series with a 10 ohm resistor and a battery with an emf of 25 V. At t = 0 the switch is closed. Find
the power dissipated in the resistor

Text Solution

Verified by Experts

The power dissipated in the resistor is `P_(R) = I^(2)R = I_(0)^(2)R (1 - 2e^(-t/zeta)" +e^(-2t/zeta)`
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