Home
Class 12
PHYSICS
An inductance and a resistance are conne...

An inductance and a resistance are connected in series with an AC potential . In this circuit

Text Solution

Verified by Experts

`Z=(sqrt([R^(2)+(omegaL-(1)/(omegaC)))^(2))]=sqrt((16)^(2)+(24-12)^(2))=20ohm`
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETIC INDUCTION & ALTERNATING CURRENT

    VMC MODULES ENGLISH|Exercise SOLVED EXAMPLES|24 Videos

  • ELECTROMAGNETIC INDUCTION & ALTERNATING CURRENT

    VMC MODULES ENGLISH|Exercise PRACTICE EXERCISE 1|10 Videos

  • DYNAMICS OF A PARTICLE

    VMC MODULES ENGLISH|Exercise JEE Advance (Archive) Level - II (SINGLE OPTION CORRECT TYPE )|31 Videos

  • ELECTROMAGNETIC INDUCTION & ALTERNATIVE CURRENT

    VMC MODULES ENGLISH|Exercise IMPECCABLE|52 Videos

Similar Questions

Explore conceptually related problems

A circuit containing an inductance and a resistance connected in series, has an AC source of 200V, 50Hz connected across it. An AC current of 10A rms flows through th ecircuit and the power loss is measured to be 1W.

A resistor R an inductance L and a capacitor C are all connected in series with an ac supply The resistance of R is 16ohm and for the given frequency the inductive reactance of L is 24 ohm and the capacitive reactance of C is 12ohm If the current in the circuit is 5A find (a) the potential difference across R,L and C (b) the impedance of the circuit (c) the voltage of the ac supply and (d) the phase angle .

A resistor R an inductance L and a capacitor C are all connected in series with an ac supply The resistance of R is 16ohm and for the given frequency the inductive reactance of L is 24 ohm and the capacitive reactance of C is 12ohm If the current in the circuit is 5A find (a) the potential difference across R,L and C (b) the impedance of the circuit (c) the voltage of the ac supply and (d) the phase angle .

If resistance R =100 Omega, inductance L = 12mH and capacitance C=15muF are connected in series to an AC sources, then at resonance the impedance of circuit is

If resistance R = 10 Omega , inductance L = 2 mH and capacitance C = 5 muF are connected in series to an AC source of frequency 50 Hz, then at resonance the impedance of circuit is

A 0.21 H inductor and a 12 Omega resistance are connected in series to a 220 V, 50 Hz ac source. The current in the circuit is

An inductor of inductance L ,a capacitor of capacitance C and a resistor of resistance' R 'are connected in series to an ac source of potential difference V volts as shown in figure. Potential difference across L,C and R is 40V , 10V and 40V ,respectively.The amplitude of current flowing through LCR series circuit is 10sqrt(2)A .The impedance of the circuit is :

A capacitor (C) and a resistor (R) are connected in series with an a.c, source of voltage of frequency 50 Hz. The potential difference across C and R are respectively 120 V and 90 V. The current in the circuit is 3A. Calculate () impedance of the circuit, (i) value of the inductance which when connected in series with Cand R will make the power fador of the circuit unity.

An inductor of inductance L and ressistor of resistance R are joined in series and connected by a source of frequency omega . Power dissipated in the circuit is

A resistance of 300Omega and an inductance of 1/(pi) henry are connected in series to an AC voltage of 20 "volts" and 200Hz frequency. The phase angle between the voltage and current is